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should() for std.range.interfaces.InputRange returns ShouldObject #88

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razvanco13 opened this issue Jan 18, 2019 · 0 comments
Open

should() for std.range.interfaces.InputRange returns ShouldObject #88

razvanco13 opened this issue Jan 18, 2019 · 0 comments

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@razvanco13
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std.range.interfaces.* represents explicit interfaces for ranges.
They are both (T == interface) and isInputRange!T, but returning ShouldList is probably more natural then ShouldObject.
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@razvanco13